CYCLONE DESIGN:-
The maxth tangential velocity according to kalen and zenz is given by Max UT=22.6 gµ pp (kb)1.2 D0.201/p2f(1-kb)
We have to determine the cyclone diameter (D) by this equation
So, D0.201 = UT p2f(1-kb)/22.6 gu Pp(kb)1.2
We have been measured various parameter related to smoke particles
Exhaust volume =330 cm3
UT = 7.7 m/s = 49.203 ft/sec
g = 9.81 m/s2 = 32.2 ft/sec2
µ = 8.9×10-2 kg/m-hr = 16.61×10-6 lbs /ft- sec
Pf = 0.788 kg/m3at 175’c exhaust gas temperature.
= 0.04919 lbs/ft3
Pp = 0.9 g/cc
= 0.9×62.43 lbs/ft3 = 56.187lbs/ft3
Kb = 0.2
Substituting this value in above equation
D0.201=49.2×(0.04919)2(1-0.2)/22.6×32.2×16.61×10-6×56.187×(0.2)1.2
= 0.0952376×106/98447.747
D0.201 =0.9674
D =0.4162 ft = 0.4162/3.2802 m
D =0.125 m
D =12.5 cm =130mm
CYCLONE DESIGN CONFIGURATION:-
For selecting high efficiency
Body diameter D = 130 mm
Inlet pipe diameter a = 3.80 cm
Inlet width b = 0.21 D = 5.25 cm
Outlet length S = 0.5 D = 12.5 cm
Outlet diameter De = 0.4 D = 50 mm
Cylinder height h = 1.4 D = 180 mm
Overall height H =3.0 D = 325 mm
Dust outlet diameter B = 0.4D =52 mm
Cone height he = 145 mm
M.S sheet thickness = 2mm (16 gauge)
tell me about M.K.S system
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